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UNIT 6About 13 min + practice

Thermochemistry

Define the system, follow energy, and keep signs consistent.

What you’ll learn

  • Relate temperature changes to heat transfer.
  • Use calorimetry and enthalpy relationships.
  • Apply Hess’s law and bond-energy estimates.
01

Before you begin

The system is the part of the universe selected for analysis; surroundings are everything else relevant to energy transfer. Heat flowing into a system is positive under the usual chemistry convention. A temperature change and an energy transfer are related but not identical quantities.

Explain these starting ideas in your own words. Revisit them whenever a later step feels unclear.

02

Choose the system before choosing the sign

The system is the part under study; surroundings are everything else included in the energy accounting. Heat transferred into the system is positive under the usual convention. An exothermic reaction transfers energy to the surroundings and has negative reaction enthalpy at constant pressure.

A solution warming in a calorimeter usually means the solution gained heat while the reaction system released it. These are opposite signs. Temperature is an intensive measure, whereas heat transfer depends on amount and process. Two objects at the same temperature need not contain equal total internal energy.

03

Calorimetry measures a transfer

For a substance without a phase change, heat can be estimated from mass, specific heat, and temperature change. Include the calorimeter’s heat capacity when it is significant. In a well-insulated model, heat gained by one part equals heat lost by the other parts.

A calculation using solution mass should include all relevant solution, not just solute. If heat escapes to the room, the measured solution temperature rise for an exothermic reaction is smaller than the ideal rise. Ignoring that loss makes the calculated reaction heat magnitude too small.

q = mcΔT
q(reaction) = −[q(solution) + q(calorimeter)]

PAUSE & TRY IT

How does neglected heat loss affect the magnitude inferred for an exothermic reaction?

Reveal answer

It generally makes the measured temperature rise and calculated heat-release magnitude too small.

04

Heating curves separate temperature and phase

Within one phase, added heat changes temperature according to heat capacity. During a phase transition for a pure substance at fixed pressure, energy changes particle arrangement while temperature remains approximately constant. Use the appropriate enthalpy of fusion or vaporization for those segments.

A multistage heating problem requires adding the energy for each stage. Do not use one q = mcΔT calculation across a phase transition and assume it accounts for latent heat. Units must match whether the phase-change enthalpy is given per mole or per gram.

Energy transfer is not always a temperature changeIllustrative heating segment: rising temperature is followed by a constant-temperature phase transition. Energy added during the plateau changes phase.
Energy transfer is not always a temperature change025507510002468 Energy added (model units)Temperature (°C)Heating segment
Read figure values as text

Heating segment: 0: 20; 2: 60; 4: 100; 8: 100

PAUSE & TRY IT

What energy term is needed during melting at constant temperature?

Reveal answer

The amount multiplied by the enthalpy of fusion, with consistent units.

05

Enthalpy scales with the chemical equation

Reaction enthalpy applies to the reaction as written. Doubling every coefficient doubles the associated enthalpy; reversing the equation reverses its sign. Hess’s law works because enthalpy is a state function: the overall change depends on starting and ending states, not the route.

Standard formation enthalpies describe formation of one mole of a substance from elements in their standard states. The standard formation enthalpy of an element in its reference standard state is zero, but that does not mean the element has zero absolute energy.

ΔH°(reaction) = ΣnΔH°f(products) − ΣnΔH°f(reactants)

PAUSE & TRY IT

Why must an enthalpy value change when an equation is multiplied by three?

Reveal answer

Enthalpy is extensive; three times the reaction amount transfers three times the energy.

06

Bond energies provide an approximate molecular view

An estimated reaction enthalpy can be obtained by adding energy to break reactant bonds and subtracting energy released when product bonds form. Average bond energies refer to averages over molecular environments, so the result may differ from a calculation using substance-specific formation enthalpies.

An exothermic enthalpy does not guarantee a fast reaction, and endothermic does not automatically mean impossible. Activation energy concerns rate; entropy and temperature also matter when evaluating thermodynamic favorability. Keep these three ideas separate before combining them in Unit 9.

07

Calorimetry is an energy balance

For a material warming without a phase change, q=mcΔT. Use the mass of the material whose heat change is being calculated and an appropriate specific heat. In a simple insulated calorimeter, energy gained by the solution and calorimeter balances energy released by the reaction. The reaction’s heat has the opposite sign from the surroundings’ heat.

Include calorimeter heat capacity when provided: q_cal=C_calΔT. Heat loss to the room makes the measured temperature rise smaller for an exothermic reaction, often making the inferred magnitude of released heat too small. Distinguish this systematic loss from random thermometer noise. A careful explanation identifies where the energy went and which measured variable changed.

Two paths have the same enthalpy differenceIllustrative model, not collected experimental data. Schematic enthalpy levels: the direct change is −30; the two-step path is +20 then −50, also −30. This is a state-function comparison, not a kinetic energy barrier.
Two paths have the same enthalpy difference-40-2002000.511.52 State along chosen pathRelative enthalpy (kJ/mol)Two-step routeDirect route
Read figure values as text

Two-step route: 0: 0; 1: 20; 2: -30 • Direct route: 0: 0; 2: -30

PAUSE & TRY IT

Why can water absorb energy while its temperature remains constant during boiling?

Reveal answer

The energy supports phase change rather than increasing average kinetic energy.

08

A heating curve has two kinds of intervals

On a sloped segment, temperature changes within one phase and mcΔT is the appropriate model. On a phase-change plateau for a pure substance under the specified pressure, energy changes intermolecular organization while temperature remains approximately constant. Use amount times the relevant enthalpy of phase change on that segment.

A multistep heating problem adds all required intervals: warming the solid, melting, warming the liquid, and so on. Convert grams to moles when enthalpy is given per mole. A constant temperature does not imply zero energy transfer; it can indicate that energy is going into a phase transition. This distinction is central to reading both heating and cooling curves.

PAUSE & TRY IT

What happens to ΔH when an equation is reversed and doubled?

Reveal answer

Its sign reverses and its magnitude doubles.

09

Hess’s law is bookkeeping for a state function

Enthalpy change depends on initial and final states, so equations can be combined to obtain a target reaction. Reverse a reaction and reverse the sign of its enthalpy change. Multiply all coefficients by a factor and multiply the enthalpy by that same factor. Cancel species only after writing the scaled equations carefully.

Using standard formation enthalpies, calculate products minus reactants with each value multiplied by its coefficient. An element in its standard reference state has formation enthalpy zero by definition; this does not mean it contains no energy. Bond enthalpies provide an approximate gas-phase estimate: energy required to break bonds minus energy released when bonds form. Breaking a bond requires energy rather than releasing it.

10

Choose the system and keep the energy signs consistent

Heat describes energy transferred because of a temperature difference, not a substance stored inside matter. A system that absorbs heat has positive q under the usual convention. If a reacting system warms surrounding solution, the reaction releases energy while the solution gains it. The two signs differ because the chosen systems differ.

For an ideal insulated calorimeter, heat transfers sum to zero. Include the solution, calorimeter hardware and any other relevant heat capacities when the problem requires them. The relation q=mcΔT applies to sensible temperature change with an appropriate specific heat; it is not the complete model for melting, vaporization or a reaction’s molar enthalpy.

A temperature rise is not itself a heat amount. Mass and heat capacity matter. Equal heat inputs can produce different temperature changes, and equal temperature changes can correspond to different heat inputs. An experiment that loses heat to the room underestimates the magnitude inferred from solution warming alone.

PAUSE & TRY IT

Why does ignoring an absorbing calorimeter make an exothermic reaction appear less exothermic?

Reveal answer

Some released heat warmed the calorimeter rather than the solution. Counting only solution heat misses that positive heat uptake and underestimates the reaction’s released-energy magnitude.

11

Connect chemical equations to molar enthalpy

An enthalpy change belongs to a reaction as written. Multiplying all coefficients multiplies ΔH; reversing the equation reverses its sign. Before reporting kJ/mol, identify the mole basis: one mole of product, one mole of limiting reactant, or one mole of reaction units can give different numerical values.

Hess’s law works because enthalpy is a state function. Arrange equations so unwanted species cancel and desired coefficients remain. Carry the same sign reversals and scale factors into their enthalpy changes. A convenient algebraic manipulation that does not reproduce the target equation is not a valid solution.

Standard formation enthalpy refers to producing one mole of a compound from elements in their reference states. A reference-state elemental value of zero is a convention; it does not mean the substance contains no energy or has bonds that require no energy to break. In formation-enthalpy calculations, weight every value by its coefficient and use products minus reactants.

12

Read heating curves and bond-energy estimates physically

On a single-phase part of a heating curve, added energy raises temperature according to the relevant heat capacity. During an ideal phase-change plateau at fixed pressure, temperature remains approximately constant while phase proportions change. The energy requirement is found from amount and phase-change enthalpy. A horizontal segment therefore does not mean no energy transfer.

To solve a multistage heating problem, divide the path at phase boundaries. Calculate warming in each phase and each intervening phase change separately, then add the energies. A single average temperature difference cannot replace the latent-heat terms.

Average bond energies provide an approximate gas-phase estimate: energy is required to break reactant bonds, and energy is released when product bonds form. Use broken minus formed. Bond breaking alone is endothermic; an exothermic overall reaction releases more through new interactions than it consumes in breaking old ones. Average values need not match a particular molecular environment exactly.

13

Define the calorimeter system before assigning signs

In a simple solution calorimetry model, q solution=mcΔT. If the solution warms, its q is positive; the reaction’s heat is approximately the negative of that value when other heat transfers are negligible. If a calorimeter heat capacity is supplied, include its heat change too.

The approximation can fail if substantial energy escapes, evaporation occurs, or the assumed heat capacity is inappropriate. Explain the direction of a resulting bias using the measured temperature change. Heat loss to the room during an exothermic reaction can reduce the observed warming and underestimate the magnitude of released heat.

Convert the reaction heat to a molar enthalpy using the amount that reacted according to the defined reaction equation. Doubling every coefficient doubles the enthalpy for that rewritten reaction. The unit kJ/mol must identify the relevant reaction amount.

14

Use Hess’s law and bond energies for different purposes

Hess’s law adds reaction enthalpies because enthalpy is a state function. Reversing an equation reverses its enthalpy sign; multiplying coefficients multiplies enthalpy. Cancel species algebraically to confirm the target equation before adding numbers.

Standard enthalpies of formation give reaction enthalpy through products minus reactants with stoichiometric coefficients. Elements in their standard reference states have zero standard formation enthalpy by convention, not because they contain no energy. States of matter are part of the specified reactions.

Average bond enthalpies estimate gas-phase reaction enthalpy as bonds broken minus bonds formed. Breaking bonds requires energy and forming bonds releases it. These estimates are not interchangeable with exact species-specific formation data, especially when phase changes or different molecular environments matter.

PAUSE & TRY IT

Does breaking a chemical bond release energy by itself?

Reveal answer

No. Bond breaking requires energy; bond formation releases it. Net reaction energy depends on both.

FROM IDEA TO APPLICATION

Worked examples

EXAMPLE 1

A calorimeter sign check

A reaction warms 100.0 g of solution from 22.0°C to 27.0°C. Assume c = 4.18 , negligible apparatus heat, and no heat loss. Find reaction heat.

Reveal worked solution
  1. ΔT = 5.0°C.
  2. q(solution) = 100.0 × 4.18 × 5.0 = 2,090 J.
  3. The reaction heat is the negative of the solution heat.
Result & interpretation

q(reaction) ≈ −2.1 kJ for the amount reacted, not necessarily −2.1 kJ per mole.

EXAMPLE 2

Scale Hess’s law

A → B has ΔH = +30 kJ and B → C has ΔH = −75 kJ. Find ΔH for 2C → 2A.

Reveal worked solution
  1. Adding the original steps gives A → C with ΔH = −45 kJ.
  2. Reverse to get C → A: +45 kJ.
  3. Double the equation and enthalpy.
Result & interpretation

+90 kJ for 2C → 2A.

EXAMPLE 3

Reaction heat from a temperature rise

A reaction warms 100.0 g of solution by 4.0°C. Use c=4.18 , neglect apparatus heat and heat loss, and find the reaction heat.

Reveal worked solution
  1. q_solution=100.0×4.18×4.0=1,672 J.
  2. The solution gains energy, so its heat is positive.
  3. The reaction releases the same energy under the assumptions.
Result & interpretation

q_reaction≈−1.7 kJ for the reacting amount specified.

EXAMPLE 4

Turn calorimetry into molar enthalpy

A reaction involving 0.0250 mol limiting reactant warms 100 g solution by 3.00 K. Use c=4.18 J g-1 K-1 and neglect other heat capacities.

Reveal worked solution
  1. Solution heat is 100×4.18×3.00=1254 J.
  2. Reaction heat is −1254 J under the insulated approximation.
  3. Divide by 0.0250 mol and convert J to kJ: −50.2 kJ/mol.
Result & interpretation

The molar reaction heat is approximately −50.2 kJ per mole of the specified limiting reactant.

EXAMPLE 5

Include the calorimeter

A reaction warms 100 g of solution by 2°C. Use c=4.18 and calorimeter heat capacity 50 J/°C.

Reveal worked solution
  1. Solution gains 836 J.
  2. Calorimeter gains 100 J.
  3. Reaction heat is approximately −936 J if other transfers are negligible.
Result & interpretation

q reaction≈−0.936 kJ.

EXAMPLE 6

Reverse and scale a reaction

A→B has ΔH=−40 kJ. What is ΔH for 2B→2A?

Reveal worked solution
  1. Reversal gives +40 kJ.
  2. Doubling gives +80 kJ.
Result & interpretation

+80 kJ for the rewritten reaction.

MAKE THE DISTINCTION

Common mistakes, clearer reasoning

The trapA warmer solution means the reaction has positive ΔH.

The better explanationThe solution gained heat; the reaction released it and has negative heat under the insulated model.

The trapFormation enthalpy is zero for every elemental molecule in every state.

The better explanationZero applies to an element’s reference standard state, not every allotrope or phase.

RETRIEVE BEFORE YOU REVEAL

Practice checkpoints

Revisit the quick checks from this guide without looking back. Explain why, then reveal the answer.

1. Why must an enthalpy value change when an equation is multiplied by three?

Reveal answer

Enthalpy is extensive; three times the reaction amount transfers three times the energy.

2. What energy term is needed during melting at constant temperature?

Reveal answer

The amount multiplied by the enthalpy of fusion, with consistent units.

3. How does neglected heat loss affect the magnitude inferred for an exothermic reaction?

Reveal answer

It generally makes the measured temperature rise and calculated heat-release magnitude too small.

4. Why can water absorb energy while its temperature remains constant during boiling?

Reveal answer

The energy supports phase change rather than increasing average kinetic energy.

5. What happens to ΔH when an equation is reversed and doubled?

Reveal answer

Its sign reverses and its magnitude doubles.

6. Why does ignoring an absorbing calorimeter make an exothermic reaction appear less exothermic?

Reveal answer

Some released heat warmed the calorimeter rather than the solution. Counting only solution heat misses that positive heat uptake and underestimates the reaction’s released-energy magnitude.

7. Does breaking a chemical bond release energy by itself?

Reveal answer

No. Bond breaking requires energy; bond formation releases it. Net reaction energy depends on both.

Key language

Enthalpy
A state function whose change equals heat at constant pressure under the usual work assumptions.
Specific heat
Heat required per unit mass for a unit temperature increase.
State function
A quantity determined by state rather than path.
Calorimetry
Measurement of energy transfer using thermal observations.
Connect it to the course

Enthalpy is one contribution to Gibbs energy and thermodynamic favorability.

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Written for ScienceHub · Original instructional material. Course framework reference ↗. These notes are independently authored and are not College Board materials. External photographs retain their credited licenses.

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