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Linear Momentum
Calculus-based mechanics: connect the physical model, its equations, and the evidence.
What you’ll learn
- Relate impulse to momentum change.
- Apply momentum conservation to defined systems.
- Distinguish elastic, inelastic, and explosive interactions.
- Set up and interpret derivatives or integrals with physical initial conditions.
Before you begin
Momentum is mass times velocity and is a vector. Impulse is the change in momentum produced by a force over time. A system’s momentum is conserved when its net external impulse is negligible over the interval.
Momentum is a vector
Linear momentum is mass times velocity. Its sign or direction matters, so opposing motions can cancel in the total even when both objects move rapidly. An isolated two-object system can have zero total momentum and substantial kinetic energy. Momentum and kinetic energy therefore encode different information.
Impulse is the integral of force over time, represented by signed area under a force–time graph. For a constant or average force, impulse is force times duration. The net external impulse equals the system’s momentum change.
PAUSE & TRY IT
Why do internal forces not change total system momentum?
Reveal answer
Their equal and opposite impulses cancel in the total.
Conservation follows from a small external impulse
Total system momentum is conserved when the net external impulse is zero or negligible over the interval. Internal force pairs produce equal and opposite impulses that cancel in the total. Choose the system to include both interacting objects when using collision conservation.
External forces need not be literally absent. During a short horizontal collision, friction may produce a negligible impulse compared with the collision forces. State that approximation rather than claiming gravity and normal force disappear. Over a longer interval, previously negligible forces may matter.
Read figure values as text
Illustrative force pulse: 0: 0; 0.2: 20; 0.4: 0
PAUSE & TRY IT
Can an explosion increase kinetic energy without increasing momentum?
Reveal answer
Yes. Stored internal energy becomes kinetic energy while fragment momenta can sum to the original total.
Collisions do not all conserve kinetic energy
An elastic collision conserves total kinetic energy as well as momentum for the appropriately isolated system. An inelastic collision converts some kinetic energy to internal energy. In a perfectly inelastic collision, objects stick together and share a final velocity.
Momentum can remain conserved even when kinetic energy decreases. Applying kinetic-energy conservation to a sticking collision usually gives an incorrect result. Use momentum first, then compare kinetic energies if asked about energy transformed.
PAUSE & TRY IT
What determines whether friction can be neglected during a collision?
Reveal answer
Its external impulse over the collision interval relative to the momentum changes of interest.
Explosions convert stored energy to motion
An explosion or spring release can increase system kinetic energy while total momentum remains conserved. If the system begins at rest, its final momenta sum to zero, but the fragments’ speeds need not match. The smaller mass has the larger speed magnitude for two fragments with equal and opposite momenta.
The center of mass moves according to the net external force. Internal interactions can greatly change individual motions without changing center-of-mass motion in an isolated system. This is useful when a system separates into pieces.
Force duration explains impact design
For a fixed momentum change, increasing stopping time reduces the magnitude of average force. Cushions and airbags can extend the interaction time and distance. This does not guarantee the same peak force for every force-time shape; average and maximum force are distinct.
A bouncing object can have a greater momentum change than one that merely stops because its velocity reverses. Choose signs and compute final minus initial momentum. A force-time graph may contain both positive and negative regions, which contribute signed impulses.
Use impulse when force is brief or variable
Area under a force–time graph gives impulse. For a triangular pulse, use one-half base times height; for a rectangular pulse, use base times height. The peak force can be much larger than the average force. The same momentum change over a longer collision time requires a smaller average force, which explains many protective designs.
Choose the sign of the force consistently with the velocity direction. A ball rebounding from a wall changes momentum by more than a ball that merely stops from the same initial speed. Calculate final minus initial momentum with signed velocities rather than subtracting speed magnitudes.
Read figure values as text
Short contact: 0: 20; 0.2: 20; 0.2: 0; 0.4: 0 • Long contact: 0: 10; 0.4: 10
PAUSE & TRY IT
Does a frictionless surface guarantee an elastic collision?
Reveal answer
No. Internal deformation and heating can reduce kinetic energy during the collision.
Separate the collision from what happens afterward
During a short collision, external forces may have negligible impulse even if they matter later. Use momentum conservation for the collision interval, then an energy or force model for subsequent motion. A ballistic-pendulum-style situation, for example, can use momentum during sticking and mechanical energy during the later swing, under the appropriate assumptions.
A perfectly inelastic collision means the objects share a final velocity after sticking. Momentum can be conserved while kinetic energy decreases. In an elastic collision, both momentum and kinetic energy are conserved. Do not impose kinetic-energy conservation merely because the track is frictionless: deformation and internal motion during the collision can still convert kinetic energy.
PAUSE & TRY IT
Why can kinetic energy increase in an explosion without violating conservation?
Reveal answer
Stored internal energy is converted into kinetic energy.
Center-of-mass motion clarifies internal interactions
Internal forces can redistribute motion among parts of a system without changing its total momentum. In an explosion of an initially stationary isolated system, fragments move with momenta that sum to zero. Their kinetic energy can increase because stored internal energy is converted to motion.
The center of mass follows the motion determined by net external force. Two interacting carts can accelerate in opposite directions while the center of mass continues with constant velocity. A larger mass need not have larger momentum after an explosion; for two fragments from rest, their momentum magnitudes are equal while their speed magnitudes are inversely related to mass.
Momentum changes through impulse
Momentum p=mv is a vector. The impulse theorem Δp=∫F_external dt integrates the net force over a time interval. A large force acting briefly can deliver the same impulse as a smaller force acting longer. Force-time graph height indicates force; signed area indicates momentum change.
Average force is impulse divided by contact duration. If a ball reverses, subtract its signed initial momentum from its final momentum; using only the change in speed misses the reversal. The collision can transfer substantial momentum even when kinetic energy is unchanged.
PAUSE & TRY IT
Does zero net impulse imply that force was zero at every instant?
Reveal answer
No. Positive and negative force contributions can cancel in the time integral.
Test isolation over the collision interval
A system’s total momentum is conserved when its external impulse is negligible. The system may experience external forces during the rest of its motion; what matters during a short collision is the impulse compared with the internal exchange. Gravity can often be neglected during a brief horizontal impact, but that is an approximation to justify.
In two dimensions, conserve both momentum components. Kinetic energy is an additional conserved quantity only for an elastic collision. In a completely inelastic collision, the objects stick and share a velocity. The kinetic energy lost becomes internal energy; it is not missing momentum. Work through the collision first, then use energy or force analysis for subsequent motion.
PAUSE & TRY IT
Two equal masses, one moving at v and one stationary, stick. What fraction of initial kinetic energy remains?
Reveal answer
Momentum gives final speed . The final kinetic energy is half the initial value.
Track the center of mass and the experimental signal
The center-of-mass velocity is total momentum divided by total mass. In an isolated explosion, pieces can fly apart while the center of mass continues with its original velocity. This allows a check on any proposed fragment velocities before detailed calculation.
A force sensor has a finite sampling rate and may miss a narrow peak. Integrating many data points can still estimate impulse, but clipping the peak biases the area. Compare the integrated impulse with measured momentum change, identify sensor zero offsets, and state sign conventions for both measurements. Repeated impacts should use comparable initial conditions.
PAUSE & TRY IT
Why can an explosion preserve momentum while increasing kinetic energy?
Reveal answer
Stored internal energy becomes kinetic energy while negligible external impulse preserves total momentum.
Choose the momentum system and relevant time interval
Momentum is a vector, so signs and components matter. A system’s momentum changes through external impulse. Internal interactions can be very large during a collision but cancel in the total-system momentum balance. Include both colliding bodies if you want their mutual forces to be internal.
Momentum conservation is an approximation when external impulse is negligible over the chosen interval. A short collision may satisfy this even if gravity acts throughout, because the collision impulse is much larger over that short time. Over a long subsequent slide, friction can produce a substantial external impulse. Do not extend collision conservation automatically to the entire later motion.
In two dimensions, conserve components separately under the appropriate assumptions. Adding speed magnitudes as though all momentum were in one direction loses essential vector information. Sketch the directions before writing the equation.
Use impulse and collision type to answer different questions
Impulse is area under force versus time and equals momentum change. A triangular pulse has half the area of a rectangle with the same height and duration. Increasing stopping time for the same momentum change lowers the required average force; it does not necessarily lower peak force by exactly the same factor unless pulse shape is comparable.
In an elastic collision, total kinetic energy is conserved as well as momentum. In an inelastic collision, kinetic energy changes into other forms while momentum may still be conserved for an isolated system. Perfectly inelastic objects stick together, creating a shared final velocity. Conservation of momentum alone does not mean their final kinetic energy equals the initial value.
Recoil and explosions can increase kinetic energy by converting stored internal energy. The system can begin with zero momentum and end with objects moving in opposite directions whose vector momenta sum to zero. Equal momentum magnitudes do not imply equal speeds when masses differ.
PAUSE & TRY IT
Two objects recoil from rest in an isolated system. If one has twice the mass, how do their speed magnitudes compare?
Reveal answer
Their momentum magnitudes are equal, so the object with twice the mass has half the speed.
Connect center-of-mass motion to the external force
The center of mass is a mass-weighted position. More massive objects contribute more strongly to its location. For an isolated system, the center of mass moves at constant velocity even if objects interact internally, rotate or separate.
A collision can radically change each object’s motion while leaving center-of-mass motion smooth. This is a useful consistency check on a calculation. If an initially stationary isolated pair sticks and your result gives net momentum without an external impulse, the model or arithmetic is inconsistent.
Separate stages when a collision is followed by motion under gravity or friction. Use momentum across the short impact, then energy or force methods during the later interval. Kinetic energy may be lost at impact even if mechanical energy is approximately conserved during the subsequent rise.
Choose the collision system before claiming conservation
Total momentum is conserved when net external impulse is negligible over the chosen interval. A short collision can make some external impulses small relative to collision forces, but this requires justification. Internal forces exchange momentum between objects while canceling in the system total.
Kinetic energy is conserved in an elastic collision, not in every momentum-conserving collision. In a perfectly inelastic collision, objects stick together; momentum can remain conserved while kinetic energy becomes deformation, sound, or thermal energy. “Lost kinetic energy” does not mean total energy is destroyed.
For explosions or recoil, initially internal stored energy can become kinetic energy while total momentum remains unchanged. A system initially at rest can split into pieces with equal and opposite momenta but unequal speeds when masses differ.
PAUSE & TRY IT
Can momentum be conserved while kinetic energy increases?
Reveal answer
Yes. In an explosion, internal stored energy can become kinetic energy while net external impulse remains negligible.
Impulse is a signed change, not a force label
Impulse equals Δp. A rebound can create a larger momentum change than stopping because velocity reverses sign. Write final minus initial momentum explicitly rather than subtracting speed magnitudes. Average force is impulse divided by contact time, and different force histories can have the same impulse.
The center of mass moves according to net external force. Internal rearrangements do not accelerate the system center of mass in the absence of external force. In one dimension, its position is the mass-weighted average, not the simple midpoint unless masses are equal.
An experimental collision analysis should compare total momentum before and after with uncertainty and external interactions considered. A small discrepancy may reflect measurement limits; a systematic discrepancy can suggest an omitted external impulse. Do not infer exact conservation solely from rounded numbers.
FROM IDEA TO APPLICATION
Worked examples
A sticking collision
A 2.0 kg cart moving at +3.0 sticks to a stationary 1.0 kg cart. External horizontal impulse is negligible. Find final velocity and energy change.
Reveal worked solution
- Initial momentum = 2.0 × 3.0 = 6.0 kg·.
- Combined mass = 3.0 kg, so final velocity = +2.0 .
- Initial kinetic energy is 9.0 J; final kinetic energy is 6.0 J.
Final velocity is +2.0 . Mechanical kinetic energy decreases by 3.0 J while momentum is conserved.
A rebound impulse
A 0.20 kg ball changes velocity from +5.0 to −3.0 . Find impulse.
Reveal worked solution
- Δp = m(vf − vi).
- 0.20(−3.0 − 5.0) = −1.6 kg·.
−1.6 N·s. The direction is opposite the initial positive motion.
A rebound impulse
A 0.20 kg ball approaches a wall at +5.0 and rebounds at −4.0 . Find impulse on the ball.
Reveal worked solution
- Initial momentum is 0.20(5.0)=1.0 kg·.
- Final momentum is 0.20(−4.0)=−0.80 kg·.
- Impulse equals final minus initial momentum.
−1.80 N·s. Its magnitude is 1.80 N·s, directed away from the wall.
A shaped force pulse
A 2 kg cart initially moves at −1 . A positive triangular net-force pulse lasts 0.6 s with peak 20 N. Find final velocity.
Reveal worked solution
- Impulse is the triangle area: ()(0.6)(20)=6 N·s.
- Initial momentum is 2(−1)=−2 kg·.
- Final momentum is −2+6=4 kg·; divide by the mass.
Final velocity is +2 .
Separate collision and later motion
A 2.0 kg cart moving at 3.0 sticks to a stationary 1.0 kg cart. Find final speed and kinetic-energy change.
Reveal worked solution
- Initial momentum is 2.0(3.0)=6.0 kg .
- Combined mass is 3.0 kg, so final velocity is 2.0 .
- Initial kinetic energy is 9.0 J; final kinetic energy is 6.0 J.
The carts move at 2.0 and kinetic energy decreases by 3.0 J, converted into other forms.
A rebound impulse
A 0.2 kg ball approaches a wall at +8 and rebounds at −6 .
Reveal worked solution
- Δp=m(vf−vi)=0.2(−6−8)=−2.8 kg·.
- If contact lasts 0.02 s, average force is .
Impulse is −2.8 N·s and average force is −140 N.
Recoil speeds
A 1 kg and 3 kg piece separate from rest with no external impulse. The 1 kg piece moves at +6 .
Reveal worked solution
- Initial total momentum is zero.
- 1(6)+3v=0.
The 3 kg piece moves at −2 .
MAKE THE DISTINCTION
Common mistakes, clearer reasoning
The trapMomentum conservation means kinetic-energy conservation.
The better explanationMomentum can be conserved in an inelastic collision while kinetic energy is converted to internal energy.
The trapA longer stop changes the required impulse for the same initial and final velocities.
The better explanationThe impulse is fixed by momentum change; the average force changes.
RETRIEVE BEFORE YOU REVEAL
Practice checkpoints
Revisit the quick checks from this guide without looking back. Explain why, then reveal the answer.
1. Why do internal forces not change total system momentum?
Reveal answer
Their equal and opposite impulses cancel in the total.
2. Can an explosion increase kinetic energy without increasing momentum?
Reveal answer
Yes. Stored internal energy becomes kinetic energy while fragment momenta can sum to the original total.
3. What determines whether friction can be neglected during a collision?
Reveal answer
Its external impulse over the collision interval relative to the momentum changes of interest.
4. Does a frictionless surface guarantee an elastic collision?
Reveal answer
No. Internal deformation and heating can reduce kinetic energy during the collision.
5. Why can kinetic energy increase in an explosion without violating conservation?
Reveal answer
Stored internal energy is converted into kinetic energy.
6. Does zero net impulse imply that force was zero at every instant?
Reveal answer
No. Positive and negative force contributions can cancel in the time integral.
7. Two equal masses, one moving at v and one stationary, stick. What fraction of initial kinetic energy remains?
Reveal answer
Momentum gives final speed . The final kinetic energy is half the initial value.
8. Why can an explosion preserve momentum while increasing kinetic energy?
Reveal answer
Stored internal energy becomes kinetic energy while negligible external impulse preserves total momentum.
9. Two objects recoil from rest in an isolated system. If one has twice the mass, how do their speed magnitudes compare?
Reveal answer
Their momentum magnitudes are equal, so the object with twice the mass has half the speed.
10. Can momentum be conserved while kinetic energy increases?
Reveal answer
Yes. In an explosion, internal stored energy can become kinetic energy while net external impulse remains negligible.
Key language
- Perfectly inelastic collision
- A collision in which objects stick together.
- Center of mass
- The mass-weighted average position of a system.
- Impulse
- The time integral of force, equal to momentum change.
- Isolated system
- A system with negligible external impulse over the interval considered.
- Elastic collision
- A collision conserving total kinetic energy as well as momentum for an isolated system.
- Completely inelastic collision
- A collision in which objects stick together after impact.
Angular momentum applies the same system-and-external-interaction reasoning to rotation.